Problem 54 To prepare for Section \(4.2,\) ... [FREE SOLUTION] (2024)

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Chapter 4: Problem 54

To prepare for Section \(4.2,\) review solving equations and formulas (Sections2.2 and 2.3 ). Solve. [ 2.2] $$ 6 y-3(5-2 y)=4 $$

Short Answer

Expert verified

y = \frac{19}{12}

Step by step solution

01

- Distribute

Distribute the \( -3 \) through the parentheses: \[ 6y - 3(5 - 2y) = 4 \Rightarrow 6y - 3 \cdot 5 + 3 \cdot 2y = 4 \Rightarrow 6y - 15 + 6y = 4 \]

02

- Combine Like Terms

Combine the \( 6y \) terms: \[ 6y + 6y - 15 = 4 \Rightarrow 12y - 15 = 4 \]

03

- Isolate the Variable

Add \( 15 \) to both sides to isolate the term with \( y \): \[ 12y - 15 + 15 = 4 + 15 \Rightarrow 12y = 19 \]

04

- Solve for y

Divide both sides by \( 12 \): \[ y = \frac{19}{12} \]

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

distributive property

The distributive property is a fundamental algebraic rule that allows us to simplify expressions. It states that multiplying a sum by a number gives the same result as multiplying each addend by the number and then adding the products. The property can be written in two ways: \ \ The exercise begins by applying the distributive property to the equation \(6y - 3(5 - 2y) = 4\): \ \ Here’s what happens: \ \ When you distribute the \(-3\) through the parentheses, you multiply \(-3\) by every term inside the parentheses: \ \[ 6y - 3(5) + 3(2y) = 4 \ \rightarrow 6y - 15 + 6y = 4 \] \ \ This step simplifies the expression, making it easier to solve. The key to mastering this concept is to remember to multiply every term inside the parentheses by the term outside.

combining like terms

Combining like terms is an essential step in simplifying equations and expressions. Like terms are terms that contain the same variable raised to the same power. For example, \(6y\) and \(6y\) are like terms because they both have the variable 'y'. \ \ In the example from the exercise, we have: \ \[ 6y - 15 + 6y = 4 \ \rightarrow 6y + 6y - 15 = 4 \] \ \ By combining the like terms, you add or subtract the coefficients of the terms. In this case, adding \(6y\) and \(6y\) gives \(12y\): \ \[ 12y - 15 = 4 \] \ \ Now, the equation is simpler and ready for the next step. This process is crucial because it reduces the number of terms and makes the equation easier to solve.

isolating the variable

Isolating the variable involves rearranging the equation to get the variable by itself on one side of the equation. This is typically done using addition, subtraction, multiplication, or division. \ \ In our example, we need to isolate the term with \(y\): \ \[ 12y - 15 = 4 \] \ \ Start by adding 15 to both sides to get rid of the constant term on the left: \ \[ 12y - 15 + 15 = 4 + 15 \rightarrow 12y = 19 \] \ \ Now, the equation is \(12y = 19\). To solve for \(y\), divide both sides by 12: \ \[ y = \frac{19}{12} \] \ \ And that's it! By isolating the variable, you have found that \(y = \frac{19}{12}\). This method can be applied to any linear equation, making it a valuable tool in algebra.

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Problem 54 To prepare for Section \(4.2,\) ... [FREE SOLUTION] (3)

Most popular questions from this chapter

When the base of a triangle is increased by \(1 \mathrm{ft}\) and the height isincreased by \(2 \mathrm{ft},\) the height changes from being two-thirds of thebase to being four-fifths of the base. Find the original dimensions of thetriangleUse a graph to estimate the solution in each of the following. Be sure to usegraph paper and a straightedge if graphing by hand.Gina's new TV service costs \(\$ 200\) for the hardware plus \(\$ 35\) per monthfor the service. After how many months has she spent \(\$ 480\) for cable TV?To prepare for Section \(4.3,\) review simplifying algebraic expressions(Section \(1.8)\) Simplify. [ 1.8] $$ 2(5 x-3 y)-5(2 x+y) $$
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Problem 54 To prepare for Section \(4.2,\) ... [FREE SOLUTION] (2024)
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